x^2+195x+7250=0

Solution for x^2+195x+7250=0 equation:

x^2+195x+7250=0

a = 1; b = 195; c = +7250;
Δ = b2-4ac
Δ = 1952-4·1·7250
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-95}{2*1}=\frac{-290}{2}
=-145
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+95}{2*1}=\frac{-100}{2}
=-50
$